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InkSoul 2023-09-25 13:03:04 +08:00
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@ -98,7 +98,7 @@ uglyURLs = false
# 名字
name = "InkSoul"
# 邮箱
email = "qingci30@163.com"
email = "blog@inksoul.top"
# 座右铭或简介
motto = ""
# 头像

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@ -53,6 +53,8 @@ date: 2022-12-24T13:05:40+08:00
- [倒代换](#倒代换)
- [指数代换](#指数代换)
- [万能代换](#万能代换)
- [除法积分](#除法积分)
- [部分相消法](#部分相消法)
- [组合积分法](#组合积分法)
- [值得记忆的定积分公式](#值得记忆的定积分公式)
- [线性代数](#线性代数)
@ -399,6 +401,27 @@ $$
原积分转化为$\int R(\frac{1-t^2}{1+t^2},\frac{2t}{1+t^2})\frac{2}{1+t^2}dt$
##### 除法积分
$$
\int \frac{u}{v}dx = \int \frac{u^{'}}{v^{'}}dx - \int (\frac{u}{v})^{'} \cdot \frac{u}{v^{'}} dx
$$
例如计算$\int \frac{x+\sin x}{1 + \cos x}dx$
$原式 = \int \frac{1+\cos x}{- \sin x}dx + \int (\frac{x+\sin x}{1+ \cos x})^{'} \cdot \frac{1+\cos x}{\sin x}dx \\\\= \int \frac{1+\cos x}{-\sin x} + \int \frac{1+\cos x}{\sin x}d(\frac{x+\sin x}{1+\cos x}) \\\\ =\frac{1+\cos x}{\sin x} \cdot \frac{x+\sin x}{1 + \cos x} - \int \frac{x+\sin x}{1+ \cos x} \cdot \frac{-\sin^2 x -(1+\cos x) - x}{\sin^2 x}dx \\\\= \frac{x+\sin x}{\sin x}$
##### 部分相消法
对于一个可视为两个函数相乘的积分,可进行拆分后相消
$原式 \rightarrow \\\\ \int f_1(x)dx + \int u(x)dv(x) \rightarrow \\\\ \int f_1(x)dx + u(x)v(x) - \int v(x)du(x) = \\\\ u(x)v(x)+C$
例如计算$\int e^{2x}(\tan x + 1)^2dx$
$原式 = \int e^{2x}(\tan^2 x + 2\tan x +1)dx \\\\= \int e^{2x}(\sec^2 x + 2\tan x)dx \\\\= \int e^{2x}\sec^2 x dx + 2\int e^{2x}\tan x dx \\\\= \int e^{2x} d\tan x + 2\int e^{2x} \tan x dx \\\\= \tan x \cdot e^{2x} -2\int \tan x e^{2x} dx + 2\int e^{2x} \tan x dx \\\\ = \tan x \cdot e^{2x} + C
$
##### 组合积分法
对于